Find the exact perpendiuclar distance between two parallel lines.
a)y=3x-2 and y=3x+3
please explain your answer
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Find the exact perpendiuclar distance between two parallel lines.
a)y=3x-2 and y=3x+3
please explain your answer
can you please do it. mainly because its a parallel, and i dont know how to sub it in
Your teacher did not show how...or you missed classes?
i wasnt in class when they taught this, but does anyone know?
You can easily use the "formula" for the distance between a point and a line. For example, you haveso you know that the point (0,-2) is on the line. So use the formula to find the distance between (0,-2) and the line
.
Or, you can skip the formula and draw the graph. Use geometry.
Hi roger1505,
1 graph the lines
2 erect a vertical line @x=1. Apoint (1,1) on line y=3x-2 is produced
3@(1,1) erect a perpendicular to y=3x+3
4 write an equation for the perpendicular
5 solve for intersection of 4 and y=3x +3
6 use distance formula to find question d
d^2 = delta y^2 + delta x^2 (slope diagram between (1,1) and solution of 5 above
There is a simple solution using trig and the slope angle of the parallel lines
Hello, roger1505!
If you are allowed to use Trigonometry, here is another solution.
Quote:
Find the exact perpendicular distance between two parallel lines: .![]()
The two lines have y- intercepts at 3 and -2, and identical slopes.Code:|
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A * /
: |@* /
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: | * C
5 | /
: + - / - - - -
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B * - - - - E
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Drawperpendicular to the line through
Let
Then the slope of
Note that
We have: .
is in a right triangle with:
Hence: .
In right triangle
Therefore: .
http://latex.codecogs.com/png.latex?...%7D%7D%7B2%7D.
This is the best and simplest way of finding the perpendicular distance between two parallel lines. Hope you get it right. (Clapping)
What is your point LJ? Already answered 2 months ago...