Two concentric circles are shown in the figure above. The chord AB of the larger circle
is tangent to the smaller circle. The area of the larger circle is twice the area of the smaller circle. What is the area of the segment of the large circle (shown in dashed lines) that is cut off by the line segment AB? (Gee, I wish the image could be larger)
Inasmuch as the radii are not given directly nor the central angle, it seems that the radius must be expressed as a function of the areas of the circle. Since the larger circles area is twice the smaller circle’s, I expressed the smaller circle’s radius as r = sq.root of A÷ pi and the larger circle’s radius as r = sq. root 2A÷ pi. The height of the triangle portion of the sector would be the radius of the smaller circle.
I would like to use the formula for the area of the segment directly, i.e. Area = ½ r2 (pi ÷ 180 * Ø – sin Ø), (for theta in degrees), but am at a loss as to how to do this without a very messy equation and not having the central angle. To solve for the sector area and substract the triangle’s area to obtain the segment area also eludes me. It seems all the triangles sides would be written in terms of something else, i.e. the larger circle’s radius.. Any help will be appreciated in how to proceed with this. Obviously, I am missing something here.