Thread: Calculating perimeter with only area of a rectangle

I wanted to know how to calculate the perimeter of a rectangle if its area is 10.
I know that A=l x w
and Perimeter = 2l + 2W
How would i go about calculating the perimeter if its a Rectangle ?

Originally Posted by MikeNoob

I wanted to know how to calculate the perimeter of a rectangle if its area is 10.
I know that A=l x w
and Perimeter = 2l + 2W
How would i go about calculating the perimeter if its a Rectangle ?

There are an infinite number of possibilities. Let .

Then from the second equation we have



Obviously the perimeter will change if you change the value of w.

Originally Posted by MikeNoob

I wanted to know how to calculate the perimeter of a rectangle if its area is 10.
I know that A=l x w
and Perimeter = 2l + 2W
How would i go about calculating the perimeter if its a Rectangle ?

.
That is not possible.

A rectangle has perimeter .

A rectangle has perimeter .

Both have area .

I dont want to create another thread for this question what if a question states to find the length and width of a rectangle if its area is 48 and perimter is 28. The way i am doing it is that i am ending up with a quadratic equation. Any suggestion.

Originally Posted by MikeNoob

I dont want to create another thread for this question what if a question states to find the length and width of a rectangle if its area is 48 and perimter is 28. The way i am doing it is that i am ending up with a quadratic equation. Any suggestion.

You can't solve a quadratic equation?

I end up with the following equation:
l(square) + 48 -14l =0
When applying the quadratic formula i dont get the answer plus i get two values .. there must be an easier and a quicker way of solving this,

Originally Posted by MikeNoob

I end up with the following equation:
l(square) + 48 -14l =0
When applying the quadratic formula i dont get the answer plus i get two values .. there must be an easier and a quicker way of solving this,

You should have . That factors nicely.

Originally Posted by MikeNoob

I end up with the following equation:
l(square) + 48 -14l =0
When applying the quadratic formula i dont get the answer plus i get two values .. there must be an easier and a quicker way of solving this,

Yes, you will get two values. What values did you get? If you use one of those values as the length, what do you get for the width?

I get 8 and 6 ? how should i know which one to use ??

Originally Posted by MikeNoob

I get 8 and 6 ? how should i know which one to use ??

One of those is length and the other is width. It does not matter which is which.