I wanted to know how to calculate the perimeter of a rectangle if its area is 10.
I know that A=l x w
and Perimeter = 2l + 2W
How would i go about calculating the perimeter if its a Rectangle ?
There are an infinite number of possibilities. Let $\displaystyle \displaystyle \begin{align*} lw = 10 \implies w = \frac{10}{l} \end{align*}$.
Then from the second equation we have
$\displaystyle \displaystyle \begin{align*} P &= 2l + 2w \\ &= 2l + 2\left(\frac{10}{l}\right) \\ &= 2l + \frac{20}{l} \end{align*}$
Obviously the perimeter will change if you change the value of w.
I dont want to create another thread for this question what if a question states to find the length and width of a rectangle if its area is 48 and perimter is 28. The way i am doing it is that i am ending up with a quadratic equation. Any suggestion.
I end up with the following equation:
l(square) + 48 -14l =0
When applying the quadratic formula i dont get the answer plus i get two values .. there must be an easier and a quicker way of solving this,