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Last edited by user654321; May 24th 2012 at 04:35 AM.
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Originally Posted by user654321 I have the following question r = 3 - 4sin (theta) and r = 1 + 6 sin (theta) How do i solve this to find the points on intersection. Thanks $\displaystyle \displaystyle \begin{align*} r &= 3 - 4\sin{\theta} \\ r &= 1 + 6\sin{\theta} \\ 1 + 6\sin{\theta} &= 3 - 4\sin{\theta} \end{align*}$ You should be able to solve for $\displaystyle \displaystyle \begin{align*} \theta \end{align*}$ at least...
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