2x+3y-5z=0
3x-y+2z=0
I have found the direction vector using the vector product. The answer in the book says the lines goes through point (2,1,1). I think the 0's are a misprint. How do I find that the line goes though that point?
2x+3y-5z=0
3x-y+2z=0
I have found the direction vector using the vector product. The answer in the book says the lines goes through point (2,1,1). I think the 0's are a misprint. How do I find that the line goes though that point?
The planes $\displaystyle p_1: 2x+3y-z=2$ and $\displaystyle p_2: 3x-y+2z = 7$ have the line of interception
$\displaystyle l:\left \{ \begin{array}{l}x=-t+\frac{23}{11} \\ y=19t - \frac8{11} \\ z= 11t\end{array}\right.$ With $\displaystyle t=\frac1{11}$ you'll get the point $\displaystyle (2,1,1)$