In rhombus ABCD, AB=18 and AC=26. Find the area of the rhombus to the nearest tenth.

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- May 10th 2012, 08:46 AMGhitaBelghitiArea of Figures and Similar Figures
In rhombus ABCD, AB=18 and AC=26. Find the area of the rhombus to the nearest tenth.

- May 10th 2012, 09:04 AMprincepsRe: Area of Figures and Similar Figures
From equation :

$\displaystyle |AB|^2=\left(\frac{|AC|}{2}\right)^2+\left(\frac{| BD|}{2}\right)^2$

you can find value of $\displaystyle |BD|$ an after that calculate area$\displaystyle A$ :

$\displaystyle A=\frac{|AC|\cdot |BD|}{2}$ - May 10th 2012, 09:08 AMskeeterRe: Area of Figures and Similar Figures
have you made a sketch?

area, $\displaystyle A = \frac{d_1 \cdot d_2}{2}$

where $\displaystyle d_1$ and $\displaystyle d_2$ are diagonal lengths ... you should also know that the diagonals of a rhombus are perpendicular and bisect each other.

hmmm ... Pythagoras?