I have a circle whose center is at point (5,-2) and goes through (1,1)

Circle formula: $\displaystyle (x-h)^2+(y-k)^2=r^2$

h=5

k=-2

$\displaystyle r=\sqrt((x_1-x_2)^2+y_1-y_2)^2)$

$\displaystyle r=\sqrt((5-1)^2+(-2-1)^2)$

$\displaystyle r=\sqrt(25)=5$

so,

$\displaystyle (x-5)^2+(y+2)^2=25$

I can't tell for sure if this passes through (1,1) or not from the wolfram graph but looks pretty close.

For polar I'm not sure how to approach this so this is my attempt:

$\displaystyle (x-5)^2+(y+2)^2=25$=$\displaystyle x^2-10x+25+y^2+4x+4=5=25$

=$\displaystyle x^2-10x+y^2+4x=5=25-29$

making the substitutions for x and y:

=$\displaystyle (rcos(\theta))^2-10rcos(\theta)+(rsin(\theta))^2+4rsin(\theta)=-4$

not sure what to do here on out

thanks for help