Find the equation of the normal to y = x^2 - 4 which is parallel to x + 3y - 1 = 0
I found that the gradient of the normal is -1/3 if this is correct, i don't know where to go from here .. if someone could show me the steps please
Find the equation of the normal to y = x^2 - 4 which is parallel to x + 3y - 1 = 0
I found that the gradient of the normal is -1/3 if this is correct, i don't know where to go from here .. if someone could show me the steps please