Find the equation of the normal to y = x^2 - 4 which is parallel to x + 3y - 1 = 0

I found that the gradient of the normal is -1/3 if this is correct, i don't know where to go from here .. if someone could show me the steps please

Printable View

- Apr 6th 2012, 07:50 AMjessm001equation of normal to curve
**Find the equation of the normal to y = x^2 - 4 which is parallel to x + 3y - 1 = 0**

I found that the gradient of the normal is -1/3 if this is correct, i don't know where to go from here .. if someone could show me the steps please - Apr 6th 2012, 07:59 AMPlatoRe: equation of normal to curve
- Apr 6th 2012, 08:02 AMjessm001Re: equation of normal to curve
It doesn't say, that's why I got confused, I thought I was missing something

- Apr 6th 2012, 08:08 AMprincepsRe: equation of normal to curve
- Apr 6th 2012, 08:10 AMjessm001Re: equation of normal to curve
Thanks a lot :)

- Apr 6th 2012, 08:27 AMPlatoRe: equation of normal to curve