I'm currently stuck on the following question: The distance between the two points A(6, 2p) and B(p, -3) is 5√5. Find the possible values of p. Is this a simple trial and error solution?
Follow Math Help Forum on Facebook and Google+
Originally Posted by FH88 I'm currently stuck on the following question: The distance between the two points A(6, 2p) and B(p, -3) is 5√5. Find the possible values of p. Is this a simple trial and error solution? Hint : $\displaystyle \sqrt{(x_B-x_A)^2+(y_B-y_A)^2}=5 \cdot \sqrt 5$
Difference of x coordinates=6-p Difference of y coordinates=2p-(-3)=2p+3 Squaring both sides of distance formula we have (6-p)^2+(2p+3)^2=(5root5)^2=125 Remove brackets and solve equation (should get p=+2 or -2)
11^2 + 2^2 = 125.Find by trial (-5.-3) ( 6,-5) p=-5 and (6,8) (8,-3) p=8
View Tag Cloud