I'm currently stuck on the following question:

The distance between the two points A(6, 2p) and B(p, -3) is 5√5.

Find the possible values of p.

Is this a simple trial and error solution?

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- Apr 4th 2012, 11:25 PMFH88AS Geometry query
I'm currently stuck on the following question:

The distance between the two points A(6, 2p) and B(p, -3) is 5√5.

Find the possible values of p.

Is this a simple trial and error solution? - Apr 4th 2012, 11:40 PMprincepsRe: AS Geometry query
- Apr 4th 2012, 11:52 PMbiffboyRe: AS Geometry query
Difference of x coordinates=6-p

Difference of y coordinates=2p-(-3)=2p+3

Squaring both sides of distance formula we have (6-p)^2+(2p+3)^2=(5root5)^2=125

Remove brackets and solve equation (should get p=+2 or -2) - Apr 5th 2012, 01:30 PMbjhopperRe: AS Geometry query
11^2 + 2^2 = 125.Find by trial (-5.-3) ( 6,-5) p=-5 and (6,8) (8,-3) p=8