I'm currently stuck on the following question:

The distance between the two points A(6, 2p) and B(p, -3) is 5√5.

Find the possible values of p.

Is this a simple trial and error solution?

Printable View

- April 4th 2012, 10:25 PMFH88AS Geometry query
I'm currently stuck on the following question:

The distance between the two points A(6, 2p) and B(p, -3) is 5√5.

Find the possible values of p.

Is this a simple trial and error solution? - April 4th 2012, 10:40 PMprincepsRe: AS Geometry query
- April 4th 2012, 10:52 PMbiffboyRe: AS Geometry query
Difference of x coordinates=6-p

Difference of y coordinates=2p-(-3)=2p+3

Squaring both sides of distance formula we have (6-p)^2+(2p+3)^2=(5root5)^2=125

Remove brackets and solve equation (should get p=+2 or -2) - April 5th 2012, 12:30 PMbjhopperRe: AS Geometry query
11^2 + 2^2 = 125.Find by trial (-5.-3) ( 6,-5) p=-5 and (6,8) (8,-3) p=8