I don't think you've been given enough information...
How ?,i have the answer but i want to know the way to solve it .
Can you find any of the shown segments? Also, a hint: use the right triangle altitude theorem.
Get AM by Pythagoras (=8)
sinB=6/CB But from triangle ACM sinACM=8/10 So sinB=8/10 So 8/10=6/CB So CB=15/2
In triangle BCM cosB=BM/CB So 6/10=BM/15/2 BM=9/2
Really helpful ,thanks
Thank you !
Can you explain this part of your solution ?
(Using the labels of the attached diagram):
Add both equations columnwise:
Since the right side of the last equation becomes:
Collect like terms, divide through by 2 and you'll get the equation of the altitude theorem.