Originally Posted by

**SmokeDawg** Hey ALL - I'm working on this and could really use some help. Am I even going in the right direction here? Please see Attached for Diagram:

Bottom Pyramid – Apothem is half of the height = 6cm

LA = Lateral Area = ph

P = 4s

P=4(10)=40

LA = 40(12) = 480

Slant Height = √180

LA = 1/2pL

LA = ½(40)( √180) = 268.33

SA = 268.33 + B

B = 10^{2} = 100

SA = 368.33cm^{2}

Top Pyramid

Pythagorean Theorem to find 3^{rd} side

9 + 16 = C^{2 }C = 5cm

P = 4(5cm) = 20cm

LA = 20(10) = 200

LA = ½(20)( √180) = 134.16

SA = 134.16 + B

B = 5^{2} = 25

SA = 159.16cm^{2}

Add Both Surface Areas = 368.33 + 159.16 = 527.49cm^{2}