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Thread: Advanced proof of parallelograms having equal areas

  1. March 30th 2012, 07:25 AM #1
    lamp23
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    Advanced proof of parallelograms having equal areas

    SOLUTION FOUND. You can extend EF and CB until they intersect.
    Last edited by lamp23; March 30th 2012 at 12:21 PM.
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  2. March 30th 2012, 08:07 AM #2
    HallsofIvy
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    Re: Advanced proof of parallelograms having equal areas

    If all you are given is that ABCD and DEFG are parallelograms then you can't prove they have the same area- it's not true! It is not true that all parallelograms have the same area. What properties of ABCD and DEFG are you given that you haven't mentioned?
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  3. March 30th 2012, 08:09 AM #3
    emakarov
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    Re: Advanced proof of parallelograms having equal areas

    Quote Originally Posted by HallsofIvy View Post
    What properties of ABCD and DEFG are you given that you haven't mentioned?
    Well, the picture shows obviously that A\in EF and G\in CB.
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