I have a ring torus of the following proportions illustrated in the diagram below.
The diagram shows a cross section of the torus (it is not proportional)
Inner hole radius = a = 5.920118575210524
tube radius = r = 82.983609982018226
I am interested in surface areas.
I know how to calculate the total surface area of the torus.
But how can I calculate the area of any horizontal strip of the surface?
I have a specific example in mind, although I would like to know the methodology too.
In the diagram there is a strip labelled d, which runs from the inner equator to a point which is c degrees above.
I have worked out that:
d=15
Therefore c = 10.3567040
How can I calculate the surface area of the torus that this strip ‘d’ covers as it rotates 360 degrees around the y axis?
I will appreciate any help anyone can give.
Thanks,
Tom