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Math Help - geometry peoplem 2 right triangles overlap and i need to find the intersecting |

  1. #1
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    Wink geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    Here is a picture and all information is included i dont care if someone solves or just tells me how it is done i just need help i started withe the Pythagorean theorem but that didnt help
    Please help thank you
    geometry peoplem 2 right triangles overlap and i need to find the intersecting |-mathh.png
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  2. #2
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    Since BCD is similar to EBF: x/y = 100/320

    Since ABD is similar to EFD and DF = 320-y: x/(320-y) = 210/320

    That's plenty to solve for x and y.
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  3. #3
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    hint: there are two pairs of similar triangles here:

    BEF is similar to BCD
    EFD is similar to ABD

    ​edit: didn't see wilmers post
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  4. #4
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    Quote Originally Posted by SpringFan25 View Post
    ​edit: didn't see wilmers post
    I'll sue you !
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  5. #5
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    do u know how to solve this because i still need help
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  6. #6
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    similar to what wilmer said:

    BEF is similar to BCD, so
    \frac{X}{Y} = \frac{100}{320}

    X = \frac{100y}{320}


    ABD is similar to EFD, so
    \frac{210}{320} = \frac{X}{320-Y}

    \frac{210 \times(320-Y)}{320} = X


    You have a pair of simulaneous equations to solve.
    \frac{210 \times(320-Y)}{320} = \frac{100y}{320}

    solve for Y (gives about 216.774)
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  7. #7
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    Re: geometry peoplem 2 right triangles overlap and i need to find the intersecting |

    Thank a million
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