HELP!!!

The measure of the supp. of an angle exceeds 3 times the measure of the comp. of the angle by 10. Find he measure of the comp.

I do not understand this equation, please help me to understand this and how you get the answer. :confused:

Printable View

- Sep 25th 2007, 06:21 PMsk8ingkitttyCongruent Supp. and Comp.
HELP!!!

The measure of the supp. of an angle exceeds 3 times the measure of the comp. of the angle by 10. Find he measure of the comp.

I do not understand this equation, please help me to understand this and how you get the answer. :confused: - Sep 25th 2007, 06:55 PMJhevon
supplementary angles are angles that add up to 180 degrees, complimentary angles are angles that add up to 90 degrees.

so, if the original angle is $\displaystyle x$ then it's supplementary angle is $\displaystyle (180 - x)$ and it's complimentary angle is $\displaystyle (90 - x)$.

we are told that the supp. angle is 10 more degrees than 3 times the comp. angle. thus we have:

$\displaystyle 180 - x = 3(90 - x) + 10$

i think you can take it from here - Sep 26th 2007, 03:40 PMsk8ingkittty
Thank you very much for the help...

Maybe if I get stuck on another geometry problem, you could help me.

Thank you for your help.(Handshake)