hello guys a new member here..
i need help with this math problem that i got recently... its in the chapter conic sections.
the question is:
Find the equation of the tangent to the circle
if the equation of the circle is give by x^2+y^2-4x+6y-12=0 and is parallel to the line having the equation given by x+y-8=0
any help would be appreciated ..
cheers.
EDIT: last question was wrong and i updated it with a valid question.
thx for the response.
well if not that,what about this one? :
x^2+y^2-4x+6y-12=0 and parallel to line having the equation x+y-8=0.. will this work?.. im just listing out a few sums that i got recently.. ive never seen these sorta sums before.. and are totally new.. im guessing its gotta do something with comparing the radius using 2 different formulas to get a variable.. something like equating (|ax1+by1+c|)/ sqrt(A^2+b^2) which is the distance from a line and a point
and this formula: sqrt(g^2+f^2-c) which is the radius of the circle if g,f,c is known to us(which can be found using the given equation) g is -2 and f is -3..(im not sure..)
now i dont know how to proceed or i dont know if it is even the right way to approach.. ..