I believe or hope that i have solved the two cones with formula using
S.A =PIr(s+r)
=(3.14)(3)(6+3)
=3.14(3)(9)
=84.8yards
I can't seem to be able to solve for the rectangular portion of the problem.
Any help is greatly appreciated
I believe or hope that i have solved the two cones with formula using
S.A =PIr(s+r)
=(3.14)(3)(6+3)
=3.14(3)(9)
=84.8yards
I can't seem to be able to solve for the rectangular portion of the problem.
Any help is greatly appreciated
I only need to answer this question then i have completed lessons 1-10. In wishing to complete this course to return to college. I'm not asking for someone to do my work. I'm really asking is just for some direction, some ideas. Below is what i believe i have been able to solve so far. I'm not even sure if I'm using the right formula.
S.A =PIr(s+r)
=(3.14)(3)(6+3)
=3.14(3)(9)
=84.8yards
I'm slightly confused: how did you get that value for s? The way I see it, the radius of the half-cone is $\displaystyle 3$, but the height is $\displaystyle 5$, making $\displaystyle s=\sqrt{34}$ by Pythagoras. Once you know this, you can calculate the surface area of the three rectangles and the surface area of the cone and put them together.