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Math Help - Solve this line with the simplest method

  1. #1
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    Solve this line with the simplest method

    I drew up what I was asking.. I got there without angle B, and derived that first.. but threw it in there to assume anyway. You can also use the length of the chord if you wish.. just looking for the simplest method. I got there in several steps, and it's a bit of a mess.

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  2. #2
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    Re: Solve this line with the simplest method

    CB = sqrt(CD^2 +(DE+EB)^2)
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  3. #3
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    Re: Solve this line with the simplest method

    Solve DE, not CB, CB is given.
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    Re: Solve this line with the simplest method

    oops fixiing
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  5. #5
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    Re: Solve this line with the simplest method

    Quote Originally Posted by Athiril View Post
    Solve DE, not CB, CB is given.
    You can do the Math, there's only one variable in that equation. And I probably should have just said to use the Pythagorean theorem, and let you figure it out how.
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  6. #6
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    Re: Solve this line with the simplest method

    That wasn't really the point of the thread. I asked for people willing to do so to provide the simplest solve they can, not I can.

    As my solve was;

    line CA = 2CBSin(CBA/2) / Sin90 (so that you can see I split triangle CBA down the middle).

    angle ACB = Sin^-1(ABSinCBA / CA)

    angle CAD = CAB = ACB

    angle ACD = 180 - 90 - CAD

    AD = ACSinACD / Sin90

    DE = AB - AD - EB
    Last edited by Athiril; November 27th 2011 at 05:44 AM.
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  7. #7
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    Re: Solve this line with the simplest method

    Quote Originally Posted by Athiril View Post
    That wasn't really the point of the thread. I asked for people willing to do so to provide the simplest solve they can, not I can.

    As my solve was;

    line CA = 2CBSin(CBA/2) / Sin90 (so that you can see I split triangle CBA down the middle).

    angle ACB = Sin^-1(ABSinCBA / CA)

    angle CAD = CAB = ACB

    angle ACD = 180 - 90 - CAD

    AD = ACSinACD / Sin90

    DE = AB - AD - EB

    Hi Athiril,

    DE = r cos B - EB
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