So the same situation as the last..but new proof:

Given: Tangent line AE at B. Secant EC, which meets the circle at D.

Prove: <ABC = <BDC and <EBD = <BCD

http://img508.imageshack.us/img508/9254/proof2zw.jpg

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- October 15th 2011, 01:04 PMVoluxAnother Geometry Proof (Circles and Chords)
So the same situation as the last..but new proof:

Given: Tangent line AE at B. Secant EC, which meets the circle at D.

Prove: <ABC = <BDC and <EBD = <BCD

http://img508.imageshack.us/img508/9254/proof2zw.jpg - October 15th 2011, 02:10 PMPlatoRe: Another Geometry Proof (Circles and Chords)
- October 15th 2011, 02:15 PMVoluxRe: Another Geometry Proof (Circles and Chords)
By using the 2m(<BED) and etc..do you mean 2 of angle BED?

And wouldn't m(arc(CB)) - m(arc(BD)) essentially mean just arc CD? - October 15th 2011, 02:25 PMPlatoRe: Another Geometry Proof (Circles and Chords)
- October 15th 2011, 02:27 PMVoluxRe: Another Geometry Proof (Circles and Chords)
Yes I know what m means, though we aren't required to use them in class. We have never actually used 2 angles for one thing either.

I know geometry somewhat, it just happens to be that I have an A- in the class and got the harder proofs in which I am having a hard time with.

I'm not too great at where to start and justifications..or proofs in overall. Not great at them =/ - October 15th 2011, 02:50 PMVoluxRe: Another Geometry Proof (Circles and Chords)
I know arc BD = <BDC. and arc CD = <CBD.

How am I to put those together though? - October 16th 2011, 07:42 PMVoluxRe: Another Geometry Proof (Circles and Chords)
Would this work for the proof?:

1. given stuff..

2. <EBD = (1/2)(arc)BD 2. theorem used in the last proof I gave

3. <BDC = (1/2)(arc)BC 3. I AM UNSURE..help??

<DBC=(1/2)(arc)DC

<BCD=(1/2)(arc)BD

4. <ABC=(1/2)(arc)BC 4. theorem used in the last proof i gave

5. <ABC=<BDC 5. substitution

<EBD=<BCD

Also can you help me out with this next proof? SAME image as before and same given, except:

PRove: BE(SQUARED) = EC (TIMES) ED

Hint: Use similar triangles, and the theorem from #2(the proof above) - October 17th 2011, 03:59 PMbjhopperRe: Another Geometry Proof (Circles and Chords)
Hi volux,

Which triangles are similar.Define them and use proportions