Without actually seeing the diagram there is no way to answer parts (b) & (c).
However, the answer to (a) is 1: any two points determine a line.
Can you use a PAINT type program to insert the diagram?
Can someone please help. This problem is confusing and I just can't figure it out.
Definition: Points that lie on the same line are called collinear.
Not sure if you need a minimum of three points in on a same line to be considered collinear.
Question
Five point A-E, NO definite lines drawn. E, D and C appear to be in line, A is below D, B is below C
Conside points A,B,C,D and E as shown
1. If two of these points are selected at random, what is the probability that they are collinear?
2. If three of these points are selected at random, what is the probability that they are collinear?
3. If four of these points are selected at random, what is the probability that they are collinear?
O.K. then.
I thought that might be the diagram. I assume that eab are meant to be in a line.
The combination of five points taken three at a time, .
From the diagram there are only two subsets of three that are collinear. So what is the answer to (b)?
, how many subsets of four are collinear? So what is the answer to (C)?
Hello, sk8ingkittty!
From your sketch, I will assume that the layout looks like this:I further assume that are collinearCode:E D C * * * * A * B
. . and that are collinear.
There are: . pairs of points.Consider points as shown.
1. If two of these points are selected at random,
what is the probability that they are collinear?
Any two points are collinear.
. . Hence, there are pairs of collinear points.
Therefore: .
There are: . sets of three points.2. If three of these points are selected at random,
what is the probability that they are collinear?
There are 2 sets which are collinear: .
Therefore: .
There are: . sets of four points.3. If four of these points are selected at random,
what is the probability that they are collinear?
There are no sets of four points that are collinear.
Therefore: .