# Thread: SAT Test Question (Isosceles)

1. ## SAT Test Question (Isosceles)

I can't quite understand how to get the degree of the triangle the question asked for. If possible can someone spoon feed me on this one?

2. ## Re: SAT Test Question (Isosceles)

Originally Posted by vaironxxrd
I can't quite understand how to get the degree of the triangle the question asked for. If possible can someone spoon feed me on this one?
I will never do that.
But note that if $\displaystyle m\left( {\angle MAC} \right) = x$ then $\displaystyle 4x=140$.
If you have trouble with that then you have a great deal of work to do to get ready for the SAT.

3. ## Re: SAT Test Question (Isosceles)

Originally Posted by Plato
I will never do that.
But note that if $\displaystyle m\left( {\angle MAC} \right) = x$ then $\displaystyle 4x=140$.
If you have trouble with that then you have a great deal of work to do to get ready for the SAT.
I believe I still have allot to learn to get ready for my nov-5 SAT. But I'm willing to learn as much as I can, my current classes are giving me allot of work. Anyways
x=35

4. ## Re: SAT Test Question (Isosceles)

Originally Posted by vaironxxrd
x=35
Correct.

You now know that $\displaystyle {\angle MAC}=35^\circ$

What does $\displaystyle {\angle}AMC$ equal?

5. ## Re: SAT Test Question (Isosceles)

Originally Posted by vaironxxrd
I can't quite understand how to get the degree of the triangle the question asked for. If possible can someone spoon feed me on this one?

This is a very easy question.

Angle BAC = Angle BCA = (180 - 40)/2 = 70

So angle MAC = angle MCA = 35

now ,

70+ angle AMC = 180
So angle AMC = 110