Originally Posted by

**leketapis** Hi I have an exercise and I’ve been struggling for a while with that. This is it:

Find coordinates of the focus and the equation of the directrix of the parabola whose equations is:

3y"squer"=8x

The chord which passes through the focus parallel to the directix is called the latus rectum of the parabola. Shown that the latus rectum of the above parabola has length8/3.

I do not understand this exercise at all. I have always thoughts that parabola equation looks like that:

y = 4x"squer" -4x +3

Anyone know how to resolve this problem?