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**HallsofIvy** Sudharaka, I may be understanding quantumembryo's question differently than you because I would have simply said "yes, you are right". quantumembryo said " If the question takes this one step further and asks for **a** vector C that is also perpendicular to both A and B, we would merely take the cross product of AxB=C, and C would be the answer." I added the bold face. It is NOT necessary that A and B be at right angles to each other, $\displaystyle A\time B$ **will** be perpendicular to both. Also, the lengths of A and B are irrelevant because quantumembryo did not ask for any particular perpendicular, just **a** perpendicular.