Sudharaka, I may be understanding quantumembryo's question differently than you because I would have simply said "yes, you are right". quantumembryo said " If the question takes this one step further and asks for

**a** vector C that is also perpendicular to both A and B, we would merely take the cross product of AxB=C, and C would be the answer." I added the bold face. It is NOT necessary that A and B be at right angles to each other,

**will** be perpendicular to both. Also, the lengths of A and B are irrelevant because quantumembryo did not ask for any particular perpendicular, just

**a** perpendicular.