,.good day,.,need ur help with this,.,

suppose you know the equations of two lines that intersect at a certain point, and suppose you know the point of intersection,.how will you find the equation of the angle bisector of those lines???thnx,.,.

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- Sep 14th 2011, 12:12 AMaldrincabreraProblem in Angle Bisectors
,.good day,.,need ur help with this,.,

suppose you know the equations of two lines that intersect at a certain point, and suppose you know the point of intersection,.how will you find the equation of the angle bisector of those lines???thnx,.,. - Sep 14th 2011, 03:39 AMPlatoRe: Problem in Angle Bisectors
If you can use

*vector methods*then there is a simple solution.

Suppose that $\displaystyle \vec{A}~\&~\vec{B}$ are two two vectors then the vector $\displaystyle \vec{C}=\|\vec{A}\|\vec{B}+\|\vec{B}\|\vec{A}$ bisects the angle between $\displaystyle \vec{A}~\&~\vec{B}$. - Sep 14th 2011, 06:31 AMpiscoauRe: Problem in Angle Bisectors
well...use congruence triangle, the distance from any point of the angle bisector to the two arm is equal. So apply the formula : |Au+Bv+c/sqrt(A^2+B^2)| (the distance of point (u,v) to the straight line Ax+By+c)

- Sep 14th 2011, 08:51 PMwaqarhaiderRe: Problem in Angle Bisectors
if two lines are ax+by+c=0 and dx+ey+f=0 then equation of angle bisector will be

$\displaystyle \frac{ax+by+c}{\sqrt{a^2+b^2}}$ = $\displaystyle \frac{dx+ey+f}{\sqrt{d^2+e^2}}$