I'm trying to find the existing flow through a culvert above a proposed mini-hydropower site. A stick takes 10 seconds to pass through the pipe. Please shout up if you need anymore information, and thanks.
This post belongs in other topics.Formula for mean velocity V = 1.5 R^2/3*s^1/2 Divided by n (ft sec units)
R = hydraulic radius (area of shaded area at head end)/( wetted perimeter)
s is gradient ft per ft of length
n is a roughness factor
Area 1.84 sq ft,wetted perimeter 3.47 ft,s= .012. n = .012 smooth surface
V=8.9 fps Q= VA = 8.9 *1,84= 16.4 cfs