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Math Help - Showing being even

  1. #1
    Junior Member
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    Showing being even

    In an acute triangle ABC, the point D is a foot of an altitude from vertex C. Points E and F lay respectively on sides AC and BC, while AE=AD and BF=BD. Point S is symmetrical to point C against the middle of the circle circumscribed on the triangle ABC. Show that SE=SF.

    Could you help me with this? Should I use the law of sines? I can't manage to get through it...
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  2. #2
    Super Member TheChaz's Avatar
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    Re: Showing being even

    I would feel a whole lot more inclined to think about this if you were to upload a reasonable sketch of the given conditions.

    Heck, YOU might even solve it with a good enough picture!
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  3. #3
    Junior Member
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    Re: Showing being even


    Here it is. Hope my art skills aren't as bad as mathematical..
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