Hey, I can't solve this Q which is in the prep book of a competitive exam that I'm taking. I have attached a pic of it. Please do provide an explanation on how the answer can be obtained... Thanks in advance.
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Originally Posted by SevenAces Hey, I can't solve this Q which is in the prep book of a competitive exam that I'm taking. I have attached a pic of it. Find the measures of $\displaystyle \text{arc}(AC)~\&~\text{arc}(BC)$. The measure of $\displaystyle \text{arc}(AB)$ is the angle you require.
Originally Posted by Plato Find the measures of $\displaystyle \text{arc}(AC)~\&~\text{arc}(BC)$. The measure of $\displaystyle \text{arc}(AB)$ is the angle you require. How do I do that???
Originally Posted by SevenAces How do I do that??? Look up measures of arcs in your textbook.
Originally Posted by Plato Look up measures of arcs in your textbook. There aren't any measures of arcs specified..!?!? Can you please explain me step-by-step on how to obtain the solution. I have my test tomorrow!
Hi SevenAces. Google angles between secants then regentsprep.org
Originally Posted by SevenAces Hey, I can't solve this Q which is in the prep book of a competitive exam that I'm taking. I have attached a pic of it. Please do provide an explanation on how the answer can be obtained... Thanks in advance. Angle CBA = Angle ACT = 48 degree Triangle BCT, Angle ACB = 180 - 48 - 36 - 48 = 48 degree Angle subtended by AB at the centre of circle = 2 (48) = 96 degree
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