1. ## Basic geometry proof

Given a triangle ABC and D is the midpoint of BC. Prove that

2. ## Re: Basic geometry proof

Originally Posted by MichaelLight
Given a triangle ABC and D is the midpoint of BC. Prove that
$\displaystyle \overrightarrow {DA} = \overrightarrow {AB} + \overrightarrow {BD} \;\& \,\overrightarrow {DA} = \overrightarrow {AC} + \overrightarrow {CD}$
Note that $\displaystyle \overrightarrow {BD}+\overrightarrow {CD}=0$.