You have one square + 4 triangles that make the surface area.
We know the information about the base which is also the length of the square so
solve for
The square base of a regular pyramid has a side length of 4. Each of the other 4 faces of the pyramid is a triangle with a base of 4 and a height of 6. The pyramid has a total surface area of 64. A second regular pyramid has a square base that is 4 by 4 but its total sure area is double that of the first pyramid. What is the height of each of the triangular faces of the second pyramid?
I know that the answer is 14, but is there a way to find this without knowing the formula (1/2 (p)(l) + B = TSA)? It's a practice standardized test question