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Math Help - I need help with some question please!!!! :)

  1. #1
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    I need help with some question please!!!! :)

    The equation of a parabola is given by (x^2) -4x - 2y + 8 =0*

    Find the equation of the normal at (0,4)*


    2. A woman walks 120 meters on a bearing of 312 then turns and walks for a further 96 meters on a bearing of 056*

    How far is she from her starting point,

    And find the bearing of the woman from her starting point.*


    3.
    Y=-(x-1)^2*
    Y= 2x-10*
    Intersect in forth quadrant, find the point of intersection.*
    Find x intercepts and hence find the area under the curve*

    Two straight roads run from point O. One heads west while the other heads south.*
    Person A is 24km west of point O whilst person A is 18km south of O.*
    Person A walks at 2km/h towards o, where as person B walks 4km/h away from O.*

    Show that after t hours, the area A km^2 of triangle AOB is given by:*
    A=216+30t-4t^2*

    Calculate rate of change in the area after 1 hour

    When does this triangles are start to decrease?


    the area of the sector of a circle, radius r units, subtending an angle of (theta) at the center is 100(pie)cm^2*

    Show that the perimeter of the sector can be given by*
    P= 2r + 200/r*

    Find the radius of the circle that makes the perimeter of the sector a minimum.*
    *
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  2. #2
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    Re: I need help with some question please!!!! :)

    For the first question find dy/dx at x equals 0. This will be the gradient of the tangent. You can find the normal using this.
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  3. #3
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    Re: I need help with some question please!!!! :)

    Quote Originally Posted by Deannnn View Post
    The equation of a parabola is given by (x^2) -4x - 2y + 8 =0*

    Find the equation of the normal at (0,4)*


    2. A woman walks 120 meters on a bearing of 312 then turns and walks for a further 96 meters on a bearing of 056*

    How far is she from her starting point,

    And find the bearing of the woman from her starting point.*


    3.
    Y=-(x-1)^2*
    Y= 2x-10*
    Intersect in forth quadrant, find the point of intersection.*
    Find x intercepts and hence find the area under the curve*

    Two straight roads run from point O. One heads west while the other heads south.*
    Person A is 24km west of point O whilst person A is 18km south of O.*
    Person A walks at 2km/h towards o, where as person B walks 4km/h away from O.*

    Show that after t hours, the area A km^2 of triangle AOB is given by:*
    A=216+30t-4t^2*

    Calculate rate of change in the area after 1 hour

    When does this triangles are start to decrease?


    the area of the sector of a circle, radius r units, subtending an angle of (theta) at the center is 100(pie)cm^2*

    Show that the perimeter of the sector can be given by*
    P= 2r + 200/r*

    Find the radius of the circle that makes the perimeter of the sector a minimum.*
    *
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