# finding radius and center of circles inscribed into triangles

• Aug 12th 2011, 06:37 PM
finding radius and center of circles inscribed into triangles
Hi everyone! I would like guidance on setting this problem up. I'm not actually in a geometry course so I am not sure where to begin. (Headbang)

Two triangles share a common edge. The vertices are located at the Cartesian coordinates of (1,10), (0.75, 15), (18,12), and (8,2). What is the radius and center location of the largest inscribed circle for each triangle? What is the distance between the two centers?

*If it helps, the common edge is between the coordinates (1,10) and (18,12).

I found a wiki article: Incircle and excircles of a triangle - Wikipedia, the free encyclopedia
But I don't know how to find the length of the sides. These are not right triangles.

If anyone can help with this in any way, I'd really appreciate it. Thanks in advance for your time.

• Aug 12th 2011, 07:17 PM
mido22
Re: finding radius and center of circles inscribed into triangles
Quote:

Hi everyone! I would like guidance on setting this problem up. I'm not actually in a geometry course so I am not sure where to begin. (Headbang)

Two triangles share a common edge. The vertices are located at the Cartesian coordinates of (1,10), (0.75, 15), (18,12), and (8,2). What is the radius and center location of the largest inscribed circle for each triangle? What is the distance between the two centers?

*If it helps, the common edge is between the coordinates (1,10) and (18,12).

I found a wiki article: Incircle and excircles of a triangle - Wikipedia, the free encyclopedia
But I don't know how to find the length of the sides. These are not right triangles.

If anyone can help with this in any way, I'd really appreciate it. Thanks in advance for your time.

i really don't remeber how to solve it but i can help u with that drawing in attachment
http://store2.up-00.com/Jun11/fGt05455.png
• Aug 12th 2011, 07:24 PM
Re: finding radius and center of circles inscribed into triangles
Quote:

Originally Posted by mido22
i really don't remeber how to solve it but i can help u with that drawing in attachment
http://store2.up-00.com/Jun11/fGt05455.png

this is fantastic! very similar to my sketch, with circles inscribed into each triangle!

• Aug 12th 2011, 11:30 PM
earboth
Re: finding radius and center of circles inscribed into triangles
Quote:

Hi everyone! I would like guidance on setting this problem up. I'm not actually in a geometry course so I am not sure where to begin. (Headbang)

Two triangles share a common edge. The vertices are located at the Cartesian coordinates of (1,10), (0.75, 15), (18,12), and (8,2). What is the radius and center location of the largest inscribed circle for each triangle? What is the distance between the two centers?

*If it helps, the common edge is between the coordinates (1,10) and (18,12).

I found a wiki article: Incircle and excircles of a triangle - Wikipedia, the free encyclopedia
But I don't know how to find the length of the sides. These are not right triangles.

If anyone can help with this in any way, I'd really appreciate it. Thanks in advance for your time.

1. The length of the radius of the incircle can be calculated by

$\displaystyle \rho = \dfrac{2A}{a+b+c}$

where $\displaystyle \rho$ = radius of the incircle (orange)
A = area of the triangle
a, b, c = lengthes of the sides of the triangle

2. The midpoint of an incircle is the point of intersection of two angle bisectors of the interior angles of the triangle (green). To avoid the (mostly) quite tricky calculations with angle bisectors you can use two parallels to sides of the triangle which have the distance $\displaystyle \rho$ from the sides.

3. I've attached a sketch so you can check the results of your calculations. The distance between the two midpoints is drawn in red.
• Aug 12th 2011, 11:41 PM
Re: finding radius and center of circles inscribed into triangles
Quote:

Originally Posted by earboth
1. The length of the radius of the incircle can be calculated by

$\displaystyle \rho = \dfrac{2A}{a+b+c}$

where $\displaystyle \rho$ = radius of the incircle (orange)
A = area of the triangle
a, b, c = lengthes of the sides of the triangle

i'm guessing the area would be calculated from the sides as well...but

how would i go about calculating the lengths of the sides? is it purely the distance of the coordinates? for example from 1, 10 to .8, 15, would that side just be 5?

i'm sorry if this is elementary as i mentioned, i am not taking a class that covers this.
• Aug 13th 2011, 04:46 AM
earboth
Re: finding radius and center of circles inscribed into triangles
Quote:

i'm guessing the area would be calculated from the sides as well...but

how would i go about calculating the lengths of the sides? is it purely the distance of the coordinates? for example from 1, 10 to .8, 15, would that side just be 5?

If you have the points $\displaystyle P(x_P, y_P)$ and $\displaystyle Q(x_Q, y_Q)$ then the distance $\displaystyle |\overline{PQ}| = \sqrt{(x_P - x_Q)^2+(y_P-y_Q)^2}$.
One of the many applications of the Pythagorean theorem.

Quote:

i'm sorry if this is elementary as i mentioned, i am not taking a class that covers this.
If the vertices of a polygon are determined by their coordinates then you can calculate the area by the chop-off method: You choose a rectangle whose sides are parallel to the axes and who contains completely the area in question (see attachment). Then you "cut off" those right triangles (or trapezods) which don't belong to the area. What's left is the value of the area.

With my example:
The surrounding rectangle has the area $\displaystyle a_r = 5 \cdot 6 = 30$
The areas of the triangles $\displaystyle \Delta_1 = 7.5, \Delta_2 = 4.5, \Delta_3 = 6$

Subtract the areas of the triangles from the area of the rectangle : 30 -18 = 12.

So the red-striped triangle has an area of 12 (units)
• Aug 13th 2011, 07:50 AM
Re: finding radius and center of circles inscribed into triangles
Wow, I think I understand now! I will work on these calculations and return with my results.

Thanks so much!

Quote:

Originally Posted by earboth
If you have the points $\displaystyle P(x_P, y_P)$ and $\displaystyle Q(x_Q, y_Q)$ then the distance $\displaystyle |\overline{PQ}| = \sqrt{(x_P - x_Q)^2+(y_P-y_Q)^2}$.
One of the many applications of the Pythagorean theorem.

If the vertices of a polygon are determined by their coordinates then you can calculate the area by the chop-off method: You choose a rectangle whose sides are parallel to the axes and who contains completely the area in question (see attachment). Then you "cut off" those right triangles (or trapezods) which don't belong to the area. What's left is the value of the area.

With my example:
The surrounding rectangle has the area $\displaystyle a_r = 5 \cdot 6 = 30$
The areas of the triangles $\displaystyle \Delta_1 = 7.5, \Delta_2 = 4.5, \Delta_3 = 6$

Subtract the areas of the triangles from the area of the rectangle : 30 -18 = 12.

So the red-striped triangle has an area of 12 (units)

• Sep 5th 2011, 08:19 PM