I would imagine that one would have to use the fact that the vector product of two vectors is twice the area of the triangle formed by their endpoints.
let A,B,C be vertices of triangle ABC in which B is taken as origin of reference and the position vectors of A and C are a and c A line AR parallel to BC is drawn from A.PR(P is midpoint of AB) meets AC at Q and area of triangle ACR is 2 times area of triangle ABC.
find
position vector of R
position vector of Q
(PQ/QR*AQ/QC) is equal to
i am not understanding how to use given information of area in this question