Thread: Cyclic quadrilateral.

ABCD is a cyclic quadrilateral.

angle A = 2x+4
angle B = y+3
angle C = 2y+10
angle D = 4x - 5

I have been trying to solve this question for about 2hrs now. I find the angles, but they don not add up to 360, no matter what method I try. I've tried elimination, substitution and cross multiplication. Nothing gives the answer. My worksheet is due tomorrow. Any help for this question is greatly appreciated. Thanks in advance.

Originally Posted by Booksrock

ABCD is a cyclic quadrilateral.

angle A = 2x+4
angle B = y+3
angle C = 2y+10
angle D = 4x - 5

I have been trying to solve this question for about 2hrs now. I find the angles, but they don not add up to 360, no matter what method I try. I've tried elimination, substitution and cross multiplication. Nothing gives the answer. My worksheet is due tomorrow. Any help for this question is greatly appreciated. Thanks in advance.

Does the worksheet get handed in for a grade? If so, its against MHF policy to help someone on such assignments; its not our job to do peoples homework for them.

However, I will give you one hint (I managed to find a satisfactory solution using this): In a cyclic quadrilateral, angles opposite to each other are supplementary. Another way of saying this is that any two angles that lie along the same diagonal are supplementary. Thus, to solve this problem, you'll need to "define" which angles of A,B,C and D are supplementary (unless you're provided with an image to which we do not have access).

Give it another shot and post your work! When you post your work, it makes it easier to point out any mistakes you might have made.

I hope you understand our policy on assignments that count for grades, and I hope this helps give you additional insight on how to tackle your problem!

Originally Posted by Chris L T521

Does the worksheet get handed in for a grade? If so, its against MHF policy to help someone on such assignments; its not our job to do peoples homework for them.

However, I will give you one hint (I managed to find a satisfactory solution using this): In a cyclic quadrilateral, angles opposite to each other are supplementary. Another way of saying this is that any two angles that lie along the same diagonal are supplementary. Thus, to solve this problem, you'll need to "define" which angles of A,B,C and D are supplementary (unless you're provided with an image to which we do not have access).

Give it another shot and post your work! When you post your work, it makes it easier to point out any mistakes you might have made.

I hope you understand our policy on assignments that count for grades, and I hope this helps give you additional insight on how to tackle your problem!

I assure you, its purely for practice. We will not be given grades on it.

Thank you anyway. I'll put up my work soon.

Originally Posted by Booksrock

angle A = 2x+4
angle B = y+3
angle C = 2y+10
angle D = 4x - 5

You should have no problems: A + C = 180 and B + D = 180 (as Chris indicated)...