# Complementary Angles?

• Jul 19th 2011, 10:43 PM
aldrincabrera
Complementary Angles?
,.,good day,.,
,.somethings been buggling my mind lately,.,.i have encountered this theorem on geometry,.,it says "If two angles are complementary, then both are acute"
so i have this question "is zero degree the complement of 90 degrees???if so,.then both are not acute since acute angles are angles less than 90,.,please help me with this,.,.thnx
• Jul 20th 2011, 02:55 AM
Plato
Re: Complementary Angles?
Quote:

Originally Posted by aldrincabrera
theorem on geometry,.,it says "If two angles are complementary, then both are acute" so i have this question "is zero degree the complement of 90 degrees???if

In a course in axiomatic geometry, most authors use this definition:
An angle is the union of two non-collinear rays with a common endpoint.
So that rules out both a degenerate angle and a so-called ‘straight angle’.
In fact, Jay Greenberg has the following theorem in his text:
$\left( {m\angle A} \right)^ \circ \text{ is a real number and }0<\left( {m\angle A} \right)^ \circ<180.$

So strictly speaking we would not have an angle of measure zero.
• Jul 20th 2011, 03:08 AM
aldrincabrera
Re: Complementary Angles?
,.,sir,.,i was proving the theorem and i ended up with this,.plss tell me if im doing it correctly,.
here is my proof.,
let alpha and beta be complementary angles,
then alpha + beta = 90.
we show that alpha < 90 and beta<90.
Suppose alpha >equal to 90 or beta >equal to 90,
then alpha+beta >equal to 90 in either cases.
thus alpha<90 and beta <90,.

am i wrong sir??thnx
• Jul 20th 2011, 03:21 AM
Plato
Re: Complementary Angles?
Quote:

Originally Posted by aldrincabrera
,.,sir,.,i was proving the theorem and i ended up with this,.plss tell me if im doing it correctly,.
here is my proof.,
let alpha and beta be complementary angles,
then alpha + beta = 90.
we show that alpha < 90 and beta<90.
Suppose alpha >equal to 90 or beta >equal to 90,
then alpha+beta >equal to 90 in either cases.
thus alpha<90 and beta <90,.

If the sum of two positive numbers is 90 then each must be less than 90.
• Jul 20th 2011, 03:47 AM
aldrincabrera
Re: Complementary Angles?
,.but sir,.,am i on the right track??
• Jul 20th 2011, 04:26 AM
Siron
Re: Complementary Angles?
Let $\alpha$ and $\beta$ be complementary angles so indeed:
$\alpha+\beta=90$
If you want to show: $\alpha<90$ and $\beta<90$.
You have to do that for positive numbers!

Because if you take $\alpha=-240°$ and $\beta=330$
Then $\alpha+\beta=90$ but $\beta$ is not $<90$.

So you have to assure you work with positive numbers.