Hi Forum!
I've been reviewing the things I know so far, and found this question
A line is drawn through (2,1), forming a right triangle at the 1st quadrant. Determine the centroid of the triangle with minimum area.
Now, if we have the point at (2,1), can the area decrease any further?
Isn't this the smaller area we can possibly obtain?
Why do 2+x and 1+y are necessary?
Thanks!
Hi Also sprach Zarathustra!
Thanks for your reply!
That's great to know, as well.
An alternative way to do it is with 2+x and 1+y, as I previously mentioned.
As it turns out, m=1/2
So if we plug this into your equation we get x=0 and y=0
Ok,
Using the 2+x/1+y method we'd get x=2 and y=1(the original measures)
Using it with 2+x/1+y
2+2=4
1+1=2
But that doesn't passes through point (2,1)!
Here is the original solution, if it can help anyone.
Thanks.
Hello, Zellator!
Your diagram is wrong.
A line is drawn through (2,1), forming a right triangle in the 1st quadrant.
Determine the centroid of the triangle with minimum area.
Code:| | * | B* | * (2,1) | o | ♥ * - - - + - - - - - - - * - - | A * |
The directions could have been stated more clearly.
. . A line through (2,1) and the two axes form a right triangle in the 1st quadrant.
The line through (2,1) and slope has the equation:
. .
. . . . . . . . .
Now locate the centroid of the triangle . . .
Hi Soroban!
Thanks for your reply!
That's why this looked so easy at first!
Of course!!!!
That's great to know!!!
Hahhaha yeah, it is easy now!
Thanks for your help Soroban and Also sprach Zarathustra!!
Centroid is in the point
I'll keep my head up if something like this comes again!
All the best!