i need to know the answers and how u got the answers for each of these pages i need to learn this missed lesson
ok well question is....
a golfer plays a shot from t
the ball travels 120m to p
the hole (h) is 210m from the tee
angle HTP is 22degrees
i need to know distance from p to h
the angle pht
and the area of the triangle
need formulas as to how u do it and answers
so answer as if its said write your working out
heres a link to the work i dont understand need guidance on each question soz missed this total subject
MyMaths.co.uk - ow13Trigonometry
To the golf problem:
for the first question, we can use the cosine rule (the Law of Cosines)
Just so you know:
$\displaystyle t$ is the side opposite angle $\displaystyle T$
$\displaystyle p$ is the side opposite angle $\displaystyle P$
$\displaystyle h$ is the side opposite angle $\displaystyle H$
we are given $\displaystyle p$ and $\displaystyle h$ and $\displaystyle T$ and we want to find $\displaystyle T$
By the cosine rule:
$\displaystyle t^2 = h^2 + p^2 - 2hp \cos T$
use this formula to find t.
for the second question, we can use the sine rule (the Law of Sines) now that we've found t
By the sine rule:
$\displaystyle \frac {t}{\sin T} = \frac {h}{\sin H}$
use this formula to solve for $\displaystyle H$
for the third question:
we can use the formula, $\displaystyle \mbox { Area } = \frac {1}{2}ph \sin T$
To the Pyramid question:
see the diagrams below. i drew in some lines and added some figures here. the red lines correspond to the first question, the pink lines correspond to the last question
first question: the told us E is above the midpoint, so if we drew in lines that cut the midpoint of AB at 90 degrees and the midpoint of BC at 90 degrees, they would meet at the midpoint of the base below E. I will call the midpoint o. Now see, we can construct a right-triangle, with hypotenuse of length = ? and legs of length 4 and 5.
we can find ? by using Pythagoras' Theorem.
Pythagoras' Theorem: If the hypotenuse of a right-triangle is a and the legs are b and c, then we have,
$\displaystyle a^2 = b^2 + c^2$
once we find ?, we can find another right-triangle AOE.
we know that the legs have length 13 and ? (which we found above), now we use Pythagoras' theorem again, to find AE
for the second question:
we can construct the right-triangle using the pink lines on the diagram. the legs are 13 and 4. we don't know the hypotenuse
we wish to find the angle x. we can use the tangent ratio to do this
remember, $\displaystyle \tan x = \frac {\mbox { Opposite }}{ \mbox { Adjacent }} = \frac {13}{4}$ in this case
so then $\displaystyle x = \tan^{-1} \left( \frac {13}{4}\right)$
Ok I Gtg Bed And I Need This Done Soon Plz Go To That Site And Give Me Full Answers With Working Out So I Can Learn From That Tomorrow But I Really Need Answers Tonight Plz
FIRST ANSWERS TO THE QUESTION I FIRST POSTED THEN HOW I DO PAGES 2-4 ON THAT LINK WITH FULL ANSWERS PLZ I REALLY NEED IT NOW OR IM IN BIG TROUBLE