# Math Help - Help find the area of a diamond.

1. ## Help find the area of a diamond.

for a) i get kn/2
for b) BF=3n/4k +n/4
CG=-4n/3k+n

for c) i get k=25/9

2. ## Re: Help find the area of IJKL, please see image in thread!

Originally Posted by gman111
for a) i get kn/2
for b) BF=3n/4k +n/4
CG=-4n/3k+n

for c) i get k=25/9
1. Let $|\overline{DA}|=k~\implies~|\overline{DG}|=\frac34 k$

$|\overline{CD}|=n~\implies~|\overline{CF}|=\frac34 n$

Then you know: $k \cdot n = 600$

2. Area of triangle $\Delta(CDG)$ is calculated by

$a_{\Delta(CDG)}= \frac12 \cdot |\overline{DG}| \cdot n = \frac12 \cdot \frac34 k \cdot n = \frac38 \cdot k \cdot n = 225$

3. The equations of the lines are OK. Determine the coordinates of the point of intersection, which is J:

$\frac34 \cdot \frac nk + \frac n4 = -\frac43 \cdot \frac nk + n$

Now replace $k = \frac{600}n$ and solve for n.

4. I'll leave the rest for you.