If the sides are 1 the hypothenuse is rad2. !^2 + 1^2 = (rad2)^2
If sides are 16 the hyp is 16 rad 2
If sides are 16/rad2 the hyp is 16
I am studying for the GMAT, and I have hit a snag. This is the question and answer.
The perimeter of an isosceles right triangle is 16+16 sqr root(2). What is the length of the hypoteneuse?
I know that the ratio of the sides of an isosceles right triangle is Side:Side:Side Sqr Root(2)
However, I was under the impression that the hypoteneuse is always the side that is Side Sqr Root (2)
But the answer to this question is that the hypoteneuse's length is actually 16. How can that be possible?
Label the perpendicular sides "x".
Then use Pythagoras' theorem.
so the hypotenuse length is
As the coefficients are inconsistent, we cannot solve for x right away.
Now you can use the surd conjugate to solve for x.
You should obtain