Good day,.,.can anyone please help me with the proof of this???thnx

If a quadrilateral is circumscribable, then the sum of the lengths of two opposite sides equals the sum of the lengths of the sides of the two remaining sides.

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- Jun 19th 2011, 06:24 PMaldrincabreraIf a quadrilateral is circumscribable, then the sum of the lengths of two opposite si
*Good day,.,.can anyone please help me with the proof of this???thnx*

If a quadrilateral is circumscribable, then the sum of the lengths of two opposite sides equals the sum of the lengths of the sides of the two remaining sides. - Jun 20th 2011, 02:18 AMPlatoRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
- Jun 20th 2011, 03:11 AMaldrincabreraRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
,.,.that's the thing that is making me confuse sir,.,coz i can't somehow imagine the diagram,.isn't the sum of two opposite sides longer than the sum of the other two???im confused,.,.can u help me sir??thnx

- Jun 20th 2011, 03:17 AMPlatoRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
Go to this page.

Look at the first diagram. You want to prove that $\displaystyle a+c=b+d.$ - Jun 20th 2011, 03:26 AMaldrincabreraRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
,.,thnx sir,,.does this mean (always) that side a is congruent to side d??and b with c???

- Jun 20th 2011, 03:35 AMPlatoRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
- Jun 20th 2011, 03:48 AMaldrincabreraRe: If a quadrilateral is circumscribable, then the sum of the lengths of two opposit
,.,.thanks so much sir,.,now i have a clear perception for the proof im going to make,.,.thnx