Originally Posted by
Zellator Hi Forum!
Here's a question:
Nine lines parallel to the base divide the other sides into 10 equal segments and the area in 10 distinct parts. If the area of the larger of these parts is 38, then the area of the original triangle is?
Now,we can consider the remaining 9 parts of the triangle as 9/10 of it.
But, here comes the part that I don't understand.
The area can be considered as 81/100 to the entire triangle.
I'm confused with the usage of the area here. I does makes a lot of sense,
but since we are in a triangle (the remaining 9/10 will be a triangle too) the area isn't supposed to be bh1/2?
This is kind of confusing to apply. Can someone help?
Why 81/100?