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Math Help - Height of a Scalene Trapezoid Question

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    Height of a Scalene Trapezoid Question

    If for a trapezoid , it has base1=40, base2=30, side1=12 & side2=16. How can i find the height?




    I am stumped. Since it is not isosceles i can't figure it out. Any formulas or guidance?
    Much appreciated.
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    h = \sqrt{12^2 - (10-x)^2}

    h = \sqrt{16^2 - x^2}

    solve the system
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    Skeeter equations are correct but they don't compute.This is a faulted quad If 16 is changed to 15 it computes.




    bjh
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    If side 2 will be perpendicular to that created side it has to be 16 right? Why would you change it to 15?
    Solving the system, h will be equal to (sqrt3591)/5; which then gives h=~12
    Is this the answer?
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    Quote Originally Posted by Zellator View Post
    If side 2 will be perpendicular to that created side it has to be 16 right? Why would you change it to 15?
    Solving the system, h will be equal to (sqrt3591)/5; which then gives h=~12
    Is this the answer?
    no ... x works out to be 10.6 , which is impossible. the lower left angle of the trapezoid would have to be obtuse if the other leg = 16
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    Oh, yes, I got 10.6 also. Nice!
    But I didn't know it would be impossible. Thanks!
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    I got h\approx12. i used herons formula to get the area of the triangle. then back substituted the area into A=1/2bh to get h. Was i lucky or is this another way to get the answer?
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    Quote Originally Posted by Aquameatwad View Post
    I got h\approx12. i used herons formula to get the area of the triangle. then back substituted the area into A=1/2bh to get h. Was i lucky or is this another way to get the answer?
    That should work but it's unnecessary. Just use pythagoras if you have the required side lengths
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    Thanks everyone. These are the most helpful forums ever!
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