Hi Forum

I've been kind of confused about how to get the height of an triangle only by the base and the angle of two intersecting medians.

Here is the question

Find the height of the isosceles triangle that has base of sqrt2; the medians to the legs form two right angles.

Calling P the point where the medians intersect we can get a right triangle on the base, with height sqrt2/2 (that goes to point P) and base sqrt2.

I can't remember exactly what to do to get the missing part of the height.

Thanks!

EDIT:

Ok, I got it, this one was easy!

In a isosceles triangle the median of the base is equal to the height.

And the centroid is exactly two thirds of the median!

So sqrt2/2 1/3

x 2/3

(Cross product)

x=sqrt2

h= sqrt2+sqrt2/2