Originally Posted by

**Zellator** Hi Forum

I studied parallelograms and triangles and I got to the formula of the area of both of them.

Namely, 1absinA/2 or absinA.

Naturally, an area of a triangle is also 1bh/2.

So, if we mash them up, considering that sinA=c/b

1/2 x bh = 1/2 x ab x c/b

Could this mean that bh=ac?

But this formulas work for both right angled triangles and non-right angled triangles, right?

So we can't consider sinA=c/b at all times, since the angle is not always right.

Does this has -something- to do with the Law of Sines or Cosines?

Sorry if I haven't made myself clear.

Thanks.