# Thread: Vectors: Cartesian EQN of a line

1. ## Vectors: Cartesian EQN of a line

Hi guys! Got a qns which I need help in:

The EQN of the line L and the plane pi are x-1 = (y+2)/(-2) = (z-4)/2 and 2x-y+4z = 11 respt. P is the point on the line where x = 2. N is the foot of perpendicular from point P to the plane.

I don't understand the line in RED. Does it mean P = (2, 0, 0)? When I tried to solve the qns using P = (2, 0, 0), I cant get the ans..

2. no, when you apply x=2 to the equation of the line, you'll get the values for y and z.