What is XY here?
I have this question that I am really stuck with, I have done the first part and believe I am close to solving the second part but really cannot see what to do next.
Q) ABCD is a trapezium with BC parallel to AD.
AB=3b BC=3a AD=9a
M is the midpoint of BC and N is the midpoint of AD
a) Find the vector MN in terms of a and b - which i found to be 3a-3b
b) Prove that XY is parallel to AD
if anybody could help me with this part it would be much appreciated
Thanks
sorry missed out 1 line of the question here it is again:
I have this question that I am really stuck with, I have done the first part and believe I am close to solving the second part but really cannot see what to do next.
Q) ABCD is a trapezium with BC parallel to AD.
AB=3b BC=3a AD=9a
M is the midpoint of BC and N is the midpoint of AD
a) Find the vector MN in terms of a and b - which i found to be 3a-3b
X is the midpoint of MN and Y is the midpoint of CD.
b) Prove that XY is parallel to AD
if anybody could help me with this part it would be much appreciated
Thanks
Hello, wahhdoe!
I'll solve it in my usual baby-talk way . . .
. . . Yes!
Code:: - - 3a - - : M B o * * o * * o C * * * * * * Y 3b * X o * * * * * o * * * * * * A o * * * * * o * * * * * o D N : - - - - - - - -9a - - - - - - - - :
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