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Math Help - Water fountain scale factor , volume surface area

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    Senior Member vaironxxrd's Avatar
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    Water fountain scale factor , volume surface area

    You decide that 0.25 inch in your model of a cylinder shape water fountain corresponds to 12 inches of the actual tower.

    The top of the tower has a diameter of 20 feet .
    The height of the actual tower is 32ft.

    Find the volume of the actual tower . ( I got pi*3200ft(cube) )

    Now use the result above to find the volume o the scale model I get confused here
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  2. #2
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    Quote Originally Posted by vaironxxrd View Post
    You decide that 0.25 inch in your model of a cylinder shape water fountain corresponds to 12 inches of the actual tower.

    The top of the tower has a diameter of 20 feet .
    The height of the actual tower is 32ft.

    Find the volume of the actual tower . ( I got pi*3200ft(cube) )

    Now use the result above to find the volume o the scale model I get confused here
    A scale is nothing but a proportion:

    \dfrac{model}{real} = \dfrac{0.25}{12} = \dfrac1{48}

    Now multiply this equation by "real" and you'll get:

    model = \dfrac1{48} \cdot real

    Plug in the real values to get the model measures:

    diameter\ of\ model = \dfrac1{48} \cdot 20' = \dfrac5{12}' = 5''

    and so on ...
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