Let Triangle ABC be a right triangle such that <A = 90*, AB = AC and let M be the midpoint of the side AC. Take the point P on the side BC so that AP is vertical to BM. Let H be the intersection point of AP and BM.

Find the ratio between the 2 triangles ABH and AHM

Find the ratio of BP : PC

So far the -BH^2 + HM^2 = 3 is the only equation I was able to formulate :/ Help please.