# what is the line obtained from the equation of 2 intersecting circles?

• Apr 12th 2011, 01:57 PM
juanma101285
what is the line obtained from the equation of 2 intersecting circles?
Hi, I am struggling with this problem (Angry). I do not know the properties of circles so well, so I gave the variables some values and drew, but I still don't get anything :-/. It would also be great if you could tell me how you know (what rule, etc.) you have used to answer the question. Thanks! :)

The problem says:

Let \$\displaystyle ax^2+ay^2+kx+ly+m=0\$, \$\displaystyle bx^2+by^2+px+qy+r=0\$ be two intersecting circles. Deviding the first equation by a and the second by b and subtracting, we obtain the equation of a line:

\$\displaystyle (k/a-p/b)x+(l/a-q/b)y+(m/a-r/b)=0\$.

What is this line?
• Apr 12th 2011, 02:16 PM
pickslides
Is it the line connecting the 2 points of intersection between the circles?
• Apr 12th 2011, 02:17 PM
TKHunny
Is that a line?
Does it exist for x^2 + y^2 = 1 vs. (x-5)^2 + y^2 = 1
Under what conditions on k, a, p, b, and q does it not exist?
• Apr 12th 2011, 02:27 PM
juanma101285
I am so lost... I drew and did not get a line connecting the two points of intersection, just a random line. Maybe I did it wrong, but I did it twice and got the same thing :(. Maybe there is a mistake there because it does not make much sense :-/
• Apr 12th 2011, 06:26 PM
TKHunny
For starters, the intersection is 0 points, 1 point, 2 points, or infinitely many points in a circular locus. If you are doing something that leads to a linear equation, that seems kind of magic, doesn't it? Why would you believe that would work? It might. Feel free to prove it. (Wink) Note: It does give the equation of the line, but it does NOT give the points of intersection. (Speechless)

Second, not everything that looks like that is a circle. There must be relationships between the parameters. If you enforce the relationships, you will see that it is all quite a bit simpler. Expand \$\displaystyle (x-a)^{2} + (y-b)^{2} = r^{2}\$, and put it in that standard form. You will see the necessary relationships.

Have you a particular numerical example that you find vexing?

Exploration: If there is no intersection, what does it produce? It's a line perpendicular to what?
• Apr 15th 2011, 11:54 PM
abhishekkgp
Quote:

Originally Posted by juanma101285
Hi, I am struggling with this problem (Angry). I do not know the properties of circles so well, so I gave the variables some values and drew, but I still don't get anything :-/. It would also be great if you could tell me how you know (what rule, etc.) you have used to answer the question. Thanks! :)

The problem says:

Let \$\displaystyle ax^2+ay^2+kx+ly+m=0\$, \$\displaystyle bx^2+by^2+px+qy+r=0\$ be two intersecting circles. Deviding the first equation by a and the second by b and subtracting, we obtain the equation of a line:

\$\displaystyle (k/a-p/b)x+(l/a-q/b)y+(m/a-r/b)=0\$.

What is this line?